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8x^2+5x-28=0
a = 8; b = 5; c = -28;
Δ = b2-4ac
Δ = 52-4·8·(-28)
Δ = 921
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{921}}{2*8}=\frac{-5-\sqrt{921}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{921}}{2*8}=\frac{-5+\sqrt{921}}{16} $
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